VBA DateDiff function

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Datediff Function Description

The VBA DateDiff function returns the number of time intervals between two provided Date values.

Syntax

The syntax for the DateDiff function in VBA is:

DateDiff( interval, date1, date2, [firstdayofweek], [firstweekofyear] )

Parameters

interval
A string which defines the type of date/time interval which will be returned as the unit of difference between date1 and date2. The following are acceptable interval string types:

Interval type Description
yyyy Year
q Quarter
m Month
y Day of the year
d Day
w Weekday
ww Week
h Hour
n Minute
s Second

date1
The first date used to calculate the difference.

date2
The first date used to calculate the difference.

firstdayofweek
Optional. A constant which defines assumed first day of the week. If omitted, assumes that Sunday is the first day of the week. This parameter can be one of the following values:

VBA Constant Value Description
vbUseSystem 0 Use the system settings
vbSunday 1 Sunday (default)
vbMonday 2 Monday
vbTuesday 3 Tuesday
vbWednesday 4 Wednesday
vbThursday 5 Thursday
vbFriday 6 Friday
vbSaturday 7 Saturday

firstweekofyear
Optional. A constant which defines assumed first week of the year. If omitted, assumes the week of Jan 1st. Otherwise use the following values:

VBA Constant Value Description
vbUseSystem 0 Use the system setting
vbFirstJan1 1 Use the first week that includes Jan 1st (default)
vbFirstFourDays 2 Use the first week in the year that has at least 4 days
vbFirstFullWeek 3 Use the first full week of the year

Example usage

The DateDiff function can be used in VBA code. Let’s look at some VBA DateDiff function examples:

DateDiff "yyyy", "2015/10/11", "2013/10/11"
'Result: 2

DateDiff "m", "2015/10/11", "2013/10/11"
'Result: -24

DateDiff "m", "2013/10/11", "2015/10/11"
'Result: 24

DateDiff "n", "2015/10/11 14:30", "2015/10/11 15:30"
'Result: 60

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